-[4z-(12z+1)]=1+(7z+0)

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Solution for -[4z-(12z+1)]=1+(7z+0) equation:


Simplifying
-1[4z + -1(12z + 1)] = 1 + (7z + 0)

Reorder the terms:
-1[4z + -1(1 + 12z)] = 1 + (7z + 0)
-1[4z + (1 * -1 + 12z * -1)] = 1 + (7z + 0)
-1[4z + (-1 + -12z)] = 1 + (7z + 0)

Reorder the terms:
-1[-1 + 4z + -12z] = 1 + (7z + 0)

Combine like terms: 4z + -12z = -8z
-1[-1 + -8z] = 1 + (7z + 0)
[-1 * -1 + -8z * -1] = 1 + (7z + 0)
[1 + 8z] = 1 + (7z + 0)

Reorder the terms:
1 + 8z = 1 + (0 + 7z)
Remove the zero:
1 + 8z = 1 + (7z)
1 + 8z = 1 + (7z)

Add '-1' to each side of the equation.
1 + -1 + 8z = 1 + -1 + (7z)

Combine like terms: 1 + -1 = 0
0 + 8z = 1 + -1 + (7z)
8z = 1 + -1 + (7z)

Combine like terms: 1 + -1 = 0
8z = 0 + (7z)
8z = (7z)

Solving
8z = (7z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-7z)' to each side of the equation.
8z + (-7z) = (7z) + (-7z)

Combine like terms: 8z + (-7z) = 1z
1z = (7z) + (-7z)

Combine like terms: (7z) + (-7z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0

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